MySQL中整条记录复制并插入方法 大致方法是先查出所需要复制到记录然后财插入,条件是两个表的记录结果数据类型都必须完全一样才行.
从 MSSQL 中导出一个文章表,需要插入到 PHPCMS 中的内容表 phpcms_content 去,需要做到文章可以发布到不同的栏目中去,也就是说,需要复制一条记录,并修改其 catid,再插入到表尾的位置上,代码如下:
- INSERT INTO phpcms_content (SELECT ".$r[$i]['aid']." + 520, ".$r[$i]['cateid'].", news_catid, catid, typeid, areaid, title, style, thumb, keywords, keywords, posids, url, listorder, status, userid, username, inputtime, updatetime, searchid, islink, prefix FROM phpcms_content WHERE contentid = '".$r[$i-1]['aid']."')
大致为:insert into a SELECT id+1, ...(其它字段) FROM a ;
下面PHP具体程序,代码如下:
- $query = "SELECT * FROM articleincategory ORDER BY ArticleID ";
- $result = $connector -> query($query);
- $i = 0;
- while($myrow = $connector -> fetch_array($result))
- {
- $r[$i]['aid'] = $myrow["ArticleID"];
- $r[$i]['cateid'] = $myrow["CategoryID"];
- $i++;
- }
- for($i = 0; $i < count($r); $i++)
- {
- if($i > 0)
- {
- if( $r[$i]['aid'] == $r[$i-1]['aid'] )
- {
- echo '第 '. $i. ' 条数据 '. $r[$i]['aid'] .' 与前一条数据 '. $r[$i-1]['aid'] .' 重复'.'<br/>';
- $sql = " INSERT INTO phpcms_content (SELECT ".$r[$i]['aid']." + 520, ".$r[$i]['cateid'].", news_catid, catid, typeid, areaid, title, style, thumb, keywords, keywords, posids, url, listorder, status, userid, username, inputtime, updatetime, searchid, islink, prefix FROM phpcms_content WHERE contentid = '".$r[$i-1]['aid']."') ";
- //$sql = " INSERT INTO phpcms_c_news (SELECT ".$r[$i]['aid']." + 520, template, titleintact, content, groupids_view, readpoint, author, copyfrom, paginationtype, maxcharperpage, sub_title FROM phpcms_c_news WHERE contentid = '".$r[$i-1]['aid']."') ";
- echo $sql.'<br />';
- //$result = $connector -> query($sql);
- //INSERT INTO test (SELECT id + 10, name, class, score FROM test WHERE id = '1');
- }
-
- else if( $r[$i]['aid'] != $r[$i-1]['aid'] )
- {
- $sql = " UPDATE phpcms_content SET origin_cateid = '".$r[$i]['cateid']."' WHERE contentid = '".$r[$i]['aid']."' ";
- echo $sql.'<br />';
- //$result = $connector -> query($sql);
- }
-
- }
- }
如果不需要插入,则更简单:insert into mytable (select * from mytable where id=1) ON DUPLICATE KEY UPDATE id=2; |