Question 1：Can you use a batch SQL（SQL Server培训 mySQL培训 ） or store procedure to calculating the Number of Days in a Month
Answer 1：找出当月的天数
select datepart(dd,dateadd(dd,-1,dateadd(mm,1,cast(cast(year(getdate()) as varchar)+'-'+cast(month(getdate()) as varchar)+'-01' as datetime))))
Question2：Can you use a SQL statement to calculating it!
How can I print "10 to 20" for books that sell for between $10 and $20，"unknown" for books whose price is null, and "other" for all other prices?
Answer 2：
select bookid,bookname,price=case when price is null then 'unknown'
when price between 10 and 20 then '10 to 20' else price end
from books
Question3：Can you use a SQL statement to finding duplicate values!
How can I find authors with the same last name?
You can use the table authors in datatabase pubs. I want to get the result as below:
Output:
au_lname number_dups
---------------------------------------- -----------
Ringer 2
(1 row(s) affected)
Answer 3
select au_lname,number_dups=count(1) from authors group by au_lname
Question4：Can you create a cross-tab report in my SQL Server!
How can I get the report about sale quality for each store and each quarter and the total sale quality for each quarter at year 1993?
You can use the table sales and stores in datatabase pubs.
Table Sales record all sale detail item for each store. Column store_id is the id of each store, ord_date is the order date of each sale item, and column qty is the sale qulity. Table stores record all store information.
I want to get the result look like as below:
Output:
Question10: How can I list non-contignous data?
In database pubs, I create a table test using statement as below, and I insert several row as below
Answer 10：
select id from test t where not exists(select 1 from test where id=t.id+1)
or not exists(select 1 from test where id=t.id-1)
Question11: How can I list all book with prices greather than the average price of books of the same type?
In database pubs, have a table named titles , its column named price mean the price of the book, and another named type mean the type of books.
Now I want to get the result as below:
type title price
------------ -------------------------------------------------------------------------------- ---------------------
business The Busy Executive's Database Guide 19.9900
...
...
...
...
Answer 11：
select a.type,a.title,a.price from titles a,
(select type,price=avg(price) from titles group by type)b
where a.type=b.type and a.price>b.price
试题点评：通览整个试题，我们不难发现，这份试题是针对SQL Server数据库人员的。而从难度分析上来看，这份试题也属于同类试题中比较难的了。之所以说它难，首先是限定时间的全英文试题；其次，尽管这份试题主要是考核开发能力，但却涉及到了算法的选择和性能的调优；最后，这份试题还夹进了SQL Server数据库的升级问题。因此，综上所述，我们估计这是一家从事程序外包工作的外企招聘后台开发或与后台开发相关的SQL Server高级程序员的试题。
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